Question

Find the value of K,if x-1 is a factor of the polynomial K.x^2-√2.x+1=0

Answer 1

For zero, x - 1 = 0
=> x = 1

Therefore,
k.(1)² – √2. 1 + 1 = 0
=> k – √2 + 1 = 0
=> k = √2 – 1

Answer 2

The value of K =  $\sqrt{2}$ -1

Given:

x-1 is a factor of the polynomial K.$x^2$-√2.x+1=0

To find:

The value of K

Explanation:

x-1 is a factor of the polynomial K.$x^2$-√2.x+1=0

x = 1 is the factor of the polynomial K.$x^2$-√2.x+1=0

So putting the value of x=1 we get value of k

K.$x^2$-√2.x+1=0

k×(1)² -  $\sqrt{2}$ × 1 +1 = 0

k - $\sqrt{2}$ +1 =0

   k = $\sqrt{2}$ -1

The value of K =  $\sqrt{2}$ -1

To learn more...

1)If p and q are the zeroes of the polynomial 3x2 -5x+2 write the polynomial whose zeroes are 1/p and/q

https://brainly.in/question/13720123

2)Write the polynomial in variable x whose zero is -k÷a​

https://brainly.in/question/13627968