Question

find the value of k if (x+1) is a factor of x cube+3x square +6x+k​

Answer 1

x+1=0

x=-1

p (x) = x^-3+3x^2+6x+k

p (-1) = 0

p (-1) = -1^3 + 3×-1^2 + 6×-1 +k

0 = -1 + 3 + (-6) +k

0 = -1 + 3 - 6 +k

0 = -4 + k

k = 4

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