Question

find the value of k if x=1 is a zero of the polynomial p(x)=4x^3+3x^2-4x+k​

Answer 1

Answer:-3

Step-by-step explanation:

As x=1 is a zero of p(x)

P(1)=0

p(1)=4+3-4+k=0

k=-3

Answer 2

Answer:

$p(x) = 4(1) ^{3} + 3(x) }^2 - 4 \times 1 + k \\ \\ \: \: \: \: 4 + 3 - 4 + k = 0 \\ 7 - 4 + k = 0 \\ k = - 3$