Question

find the value of K if x-1 is Factor of p(x) = 2x²+ KR+√2
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Answer 1

Answer:

solution is explained in the pic

Answer 2

given,

x-1 is the factor of p(x)

so,

x-1 =0

x=1

p(x)=

$2 {x}^{2} + kx + \sqrt{2}$

now, putting the value of x=1

p(1) = 2 + K +√2

now taking

p(1) = 0

we get,

2+k+√2=0

k= -2-√2

k= - (2+√2)