Find the value of k if (x-1) is factor of p(x) in each of following case.
i] p(x)=x2+x+k
ii] kx2-3x+k
HELP PLEASE
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Answer:
i)-2 ii)3/2
Step-by-step explanation:
In each case x-1=0
= x=-2
i) p(x)=x^2+x+k
p(1)=1+1+k=0
2+k=0
k = -2
ii) p(x)=kx^2-3x+k
p(1)=k^(1)-3(1)+k=0
k-3+k=0
2k-3=0
k=3/2
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