find the value of K if (x -1) is factor of P(x) = Kx^2 - underroot 2x +1
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Ques: Find the value of k if (x-1) is the factor of p(x)=kx²-√2x+1.
Solution: g(x)=x-1
x=1
p(x)=kx²-√2x+1
p(1)=k(1)²-√2(1)+1
0=k-√2+1k=√2-1
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