Question

find the value of k if x-1 is the factor of kx²-√2x+1

Answer 1

Step-by-step explanation:

p(x)= kx^2-root2x+1 x-1=0

p(1)= k(1)^2-root2(1)+1

= k-root2+1=0

= k= -1+root 2.

I think u Understand the answer.