Question

Find The Value of k if x+1 is the factor of p(x)=kx²-√2x+2​

Answer 1

Answer:

k = √2 - 2

Step-by-step explanation:

p(x) = kx² - √2x + 2

x + 1 is a factor of p(x)

then p(x) = 0

then , x + 1 = 0

x = -1

put x in p(x)

p(1) = k(-1)² - √2(1) + 2

k - √2 + 2 = 0

k = √2 - 2

Answer 2

Answer:

Step-by-step explanation:

If x + 1 is a factor of the given polynomial, then for x + 1 = 0, (i.e. x = -1), the value of the polynomial will become zero.

So, k(-1)² -√2(-1)+2 = 0

k + √2 + 2 = 0

k = -√2 - 2

k = -( √2 + 2) or -√2(1 + √2)