Question

Find the value of 'k' if x-1is the factor of p(x) =2x^-kx+√2

Answer 1

Answer:

answer is below

Step-by-step explanation:

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Answer 2

Given,

$p(x) = 2x {}^{2} - kx + \sqrt{2 }$

(x-1) is the factor of p(x)

$p(1) = 2 \times (1) ^{2} - k \times (1) + \sqrt{2} = 0 \\ p(1) = 2 - k + \sqrt{2 } = 0 \\ p(1) = 2 + \sqrt{2} = k \\ therefore \: k = 2 + \sqrt{2}$

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