Find the value of k if x=2 and y=1 is a solution of x+3y-k=0
Answers
Answered by
1
x+3y-k=0---(1)
given x=2 and y=1 put these values in (1)
2+3*1-k =0
2+3-k =0
5-k=0
-k = -5
therefore
k=5
given x=2 and y=1 put these values in (1)
2+3*1-k =0
2+3-k =0
5-k=0
-k = -5
therefore
k=5
Answered by
1
x+3y- k=0
x=2 y=1
2+3×1=k
k=2+3
k=5
x=2 y=1
2+3×1=k
k=2+3
k=5
Similar questions