Question

Find the value of k if (x-2) is a factor of 2x^2-3x+k

Answer 1

Answer:

x+2=0 => x=-2.

f(x)=2x^3-kx^2+3x+10.

f(-2)=2(-2)^3-k(-2)^2+3.(-2)+10=0.

-16–4k-6+10=0.

-4k =12.

k =-12/4 =-3 . Answer.

Step-by-step explanation:

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Answer 2

Put x=2 in the equation as it is a zero of the given polynomial.

and equate it to zero.

2*4+6-k=0

k=14