Find the value of k, if (x-2) is a factor of 7x^3-2x^2+x-k
Answers
Answered by
13
( X - 2 ) is a factor of the given polynomial 7X³ - 2X² + X - K.
So,
( X - 2 ) = 0
X = 2
P ( x ) = 7X³ - 2X² + X - K
Substitute X = 2 in P ( x ).
P (2) = 7 × (2)³ - 2 × (2)² + 2 - K
=> 7 × 8 - 2 × 4 + 2 - K = 0
=> 56 - 8 + 2 - K = 0
=> 58 - 8 - K = 0
=> - K.= -50
=> K = 50
So,
( X - 2 ) = 0
X = 2
P ( x ) = 7X³ - 2X² + X - K
Substitute X = 2 in P ( x ).
P (2) = 7 × (2)³ - 2 × (2)² + 2 - K
=> 7 × 8 - 2 × 4 + 2 - K = 0
=> 56 - 8 + 2 - K = 0
=> 58 - 8 - K = 0
=> - K.= -50
=> K = 50
Answered by
1
Factor=(x-2)
=x-2=0
=x=2
Put x=2
=7(2)^3-2(2)^2+x-k=0
=7×8-2×4+2-k=0
=56-8+2-k=0
=56-6-k=0
=50-k=0
=-k=-50
=k=50 ans.
Mark brainliest....
=x-2=0
=x=2
Put x=2
=7(2)^3-2(2)^2+x-k=0
=7×8-2×4+2-k=0
=56-8+2-k=0
=56-6-k=0
=50-k=0
=-k=-50
=k=50 ans.
Mark brainliest....
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