find the value of k if x-2 is a factor of p (x)=2x^2+3x-k
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The value of k is 14.
Given,
(x-2) is a factor of p(x) = 2x²+3x-k.
To Find,
The value of k.
Solution,
It is given that (x-2) is a factor of p(x) = 2x²+3x-k. So it will satisfy the polynomial.
Therefore, when we will substitute x = 2 in the polynomial then it will give the result as 0.
So,
P(2) = 0
2(2)²+3(2)-k = 0
8+6-k = 0
k = 14
Hence, the value of k is 14.
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