Question

find the value of k if (x-2) is a factor of p(x)=2x^3-6x^2+5x+k

Answer 1

here is your answer by Sujeet,

Given that factor of polynomial,

x-2=0
x=2

2x³-6x²+5x+k

Now putting the value of x in required polynomial,

2x³-6x²+5x+k
2(2)³- 6(2)² +5(2) +k=0
2*8 -6*4 +10+k=O
16-24+10+k=O
K=-16+24-10
k=-2

so,
k=-2

that's all :) :) :) :)

By Sujeet

Answer 2

let, x-2=0

x=2.

p(x)=2x^3-6x^2+5x+k.

substitute...x=2

p(2)=2(2)^3-6(2)^2+5(2)+k

=2(8)-6(4)+10+k
=16-24+10+k

transfer k to left hand side....

-k=16-24+10
=26-24
=2.

hence,k=-2.



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