Math, asked by sangam18082003rani, 10 months ago

Find the value of k, if x-2 is a factor of p(x) =2x-5kx+22​

Answers

Answered by riyajiya02
1

Answer:

x-2=0

x=2

P(2) = 2(2)-5k(2)+22 =0

4-10k+22=0

-10k = -26

K= 2.6

Step-by-step explanation:

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Answered by vanshikakosta2
1

Answer:

(x-2) is a factor of p(x) (given)

by factor theorem. p(2)=0. 2×(2)-5k×2+22=0. (4)-10k+22=0. 22+4-10k=0. 26-10k=0. 16k=0. k=-16

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