Find the value of k, if x-2 is a factor of p(x) =2x-5kx+22
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Answered by
1
Answer:
x-2=0
x=2
P(2) = 2(2)-5k(2)+22 =0
4-10k+22=0
-10k = -26
K= 2.6
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Answered by
1
Answer:
(x-2) is a factor of p(x) (given)
by factor theorem. p(2)=0. 2×(2)-5k×2+22=0. (4)-10k+22=0. 22+4-10k=0. 26-10k=0. 16k=0. k=-16
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