Question

find the value of k if x-2 is a factor of p(x) of the following case÷p(x)=x²+x+k​

Answer 1

Answer:

x-2=0

» x=2

p(x) = x²+ x + k

» p(2) =2²+2+k

» 4+2+ k=0

» 6+k=0

» k=-6

Answer 2

Step-by-step explanation:

By factor therom , if q=x-2=0 so x= 2

p(x)=x^2+x+k

Putting the value of x=2

p(2)=(2)^2+2+k=0

4+2+k=0

6+k=0so k=-6

so the answer is-6.

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