find the value of k if x-2 is a factor of p (x)=x square -5 + k
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x=2
x*2-5+k
2*2-5+k=0
4-5+k=0
k=+1
Answered by
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x-2= 0
x = 2
put x = 2 in p(x)
p(2) = 2²-5+k
since x-2 is factor therefore value of p(x) will be 0
0 = 4-5+k
0 = -1+k
k = 1
hope it will help please mark brainliest
x = 2
put x = 2 in p(x)
p(2) = 2²-5+k
since x-2 is factor therefore value of p(x) will be 0
0 = 4-5+k
0 = -1+k
k = 1
hope it will help please mark brainliest
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