find the value of k if x-2 is a factor of polynomial P(x) =2x³-6x²+5x+k
Answers
Answered by
23
Answer:
k= -2
Step-by-step explanation:
p(x)=2x³-6x²+5x+k
p(2)=2×2³-6×2²+5×2+k=0
or 16-24+10+k=0
or 2+k=0
k= -2
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Answered by
15
Answer:
°•° (x-2) is a factor of p(x)
=> x - 2 = 0
=> x = 2
p(x) = 2x³-6x²+5x+k
p(1) = 2(2)³-6(2)²+5(2)+k
= 2(8)-6(4)+10+k = 0
= 16-24+10+k = 0
= -8+10+k = 0
= 2+k = 0
= k = (-2)
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