Find the value of k if (x+2) is a factor of x^2-kx^2+6x-k.
Answers
Answered by
3
Hey there!
Let's take x + 2 = 0
Then, x = -2
Let us substitute the value in the equation :
As, x + 2 is a factor, the remainder will be zero, there fore, the equation is 0.
4 - 4k - 12 - k = 0
4 - 5k - 12 = 0
- 8 - 5k = 0
-5k = 8
k = -8/5
Hope my answer helps!
Answered by
6
HLO MATE ✋✋
Simran Here !!!!
==============================⭐⭐⭐
Given That : (x+2) is a factor of given polynomial...
So, x+2 = 0
x = - 2
Now , Putting the value of x in (x^2 - kx^2 + 6x - k )
⏩ x^2 - kx^2 + 6x - k
=> (-2)^2 - k(-2)^2 + 6(-2) - k
=> 4 - 4k - 12 - k
=> -8 - 5k =0
=> - 8 = 5k
=> k = -8/ 5...
So, The value of k is -8/5 ✔✔
===============================⭐⭐⭐
HOPE IT HELPS UH ✌✌
^_^
Simran Here !!!!
==============================⭐⭐⭐
Given That : (x+2) is a factor of given polynomial...
So, x+2 = 0
x = - 2
Now , Putting the value of x in (x^2 - kx^2 + 6x - k )
⏩ x^2 - kx^2 + 6x - k
=> (-2)^2 - k(-2)^2 + 6(-2) - k
=> 4 - 4k - 12 - k
=> -8 - 5k =0
=> - 8 = 5k
=> k = -8/ 5...
So, The value of k is -8/5 ✔✔
===============================⭐⭐⭐
HOPE IT HELPS UH ✌✌
^_^
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