Question

find the value of k if (x-2) is a factor of x³— 6x²± 12x–k​

Answer 1

Answer:

Brainlest please

Step-by-step explanation:

-2^3-6(-2)^2+12(-2)=k

-6-16+10=k

22+10=k

k=22+10

k=32

Answer 2

Answer:

8

Step-by-step explanation:

x-2=0

x=2

p(x)=x³-6x²+12x-k

p(2)=2³-6×2²+12×2-k

= 8-24+24-k

= 8-k

k=8

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