Question

Find the value of k, if x-2 is factor of p(x) = 2x2 + k x + 4. with full expainsation​

Answer 1

Answer:

Step-by-step explanation:

Apply remainder theorem

=>x - 1 =0

=> x =  1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get  

p(1) = 2(1)2 + k(1) + √2

p(1) =2 +  k  + √2

0 = 2 + √2 + k

-2 - √2 = k

- (2 + √2)  = k  

Answer is k = - (2 + √2)

Answer 2

Answer:

QUESTION:-

Find the value of k, if x-2 is factor of p(x) = 2x² + kx + 4 with full explanation!

Step-by-step explanation:

SOLUTION:-

WE KNOW

x-2=0 i.e, x=2

and P(x)=P(2)

2×(2)²+k×2+4=0

=>2×4+2k+4=0

8+2k+4=0

12+2k=0

NOW, TAKE COMMON↓

2(6 + k) = 0

Now take 2 to RHS which Makes it,

6 + k = 0/2

k+6=0

k=-6

BE BRAINLY✓