Question

find the value of k if x-2 is factor of p(x)=4x³+3x+k​

Answer 1

Step-by-step explanation:

p(x)=4x³+3x+k

x-2 is a factor of this cubic

x-2=0

x=2 put vaule in the cubic and equal to zero

p(2)=4(2)³+3(2)+k=0

=4×8 +6+k=0

=32+6+k=0

40+k=0

k= -40

Answer 2

Answer:

$Let P(x)=4 {x}^{3} + 3x + k \\ Given, \: (x−2) \:  is \: a \: factor \: of  \: P(x). \\ x - 2 = 0 \\ x = 2 \\ ∴P(1)=4 \times ({1})^{3} + 3 \times 1+ k = 0 \\ 4 + 3 + k = 0 \\ 7 + k = 0 \\ k = 7$