Math, asked by karthikeya12345, 1 year ago

find the value of k if x=2 is the solution of kx^2+2x-9=0

Answers

Answered by bishnumohanpradhan
2

if x=2

k(4)+2(2)-9=0

4k+4-9=0

4k=5

k=4/5

Answered by TooFree
7

kx² + 2x - 9 = 0


Substitute x = 2:

k(2)² + 2(2) - 9 = 0


Evaluate the brackets:

4k + 4 - 9 = 0


Combine like terms:

4x - 5 = 0


Add 5 to both sides:

4x = 5


Divide both sides by 4:

x = 5/4


Answer: k = 5/4


karthikeya12345: Thanks
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