find the value of k if x=2 is the solution of kx^2+2x-9=0
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Answered by
2
if x=2
k(4)+2(2)-9=0
4k+4-9=0
4k=5
k=4/5
Answered by
7
kx² + 2x - 9 = 0
Substitute x = 2:
k(2)² + 2(2) - 9 = 0
Evaluate the brackets:
4k + 4 - 9 = 0
Combine like terms:
4x - 5 = 0
Add 5 to both sides:
4x = 5
Divide both sides by 4:
x = 5/4
Answer: k = 5/4
karthikeya12345:
Thanks
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