Find the value of k, if x=2,y=1 is a solution of the equation2x+3y=k
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Answered by
0
2 (2)+3(1)=k
4+3=k
k=7
4+3=k
k=7
Answered by
3
X=2,Y=1
2X+3Y=k
2×2+3×1=k
4+3=k
7=k
K=7
2X+3Y=k
2×2+3×1=k
4+3=k
7=k
K=7
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