Question

find the value of k, if x=2, y=1 is a solution of the equation k-2x +3y=10.

Answer 1

Answer:-3Step-by-step explanation:let the k should be X and let solve the problem k-2x+3y =10 so, k-2×2+3×1=10k-4+3=10k-7=10 so k=7-10 that is equal to -3

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Answer 2

Given equation is k-2x+3y=10

According to question x=2,y=1

Now substituting the values of x and y in the equation k-2x+3y=10,we get,

k-(2×2)+(3×1)=10

⇒k-4+3=10

⇒k-7=10

⇒ k=10+7

⇒ k = 17

So, the value of k, if x=2,y=1 is a solution of the equation k-2x+3y=10 is 17