Question

Find the value of k if x=2 y=3 is a solution of(k+1)x-(2k+3)y-1=0

Answer 1

Answer:

The answer is -2.

Step-by-step explanation:

Answer 2

Answer:

k = -2

Step-by-step explanation:

Substitute x and y with 2 and 3 respectively.

$(k+1)2-(2k+3)3-1=0$

Add 1 to both sides: $(k+1)2-(2k+3)3-1+1=0+1$

Simplify: $(k+1)2-(2k+3)3=1$

$(k+1)2= 2k+2$

$(2k+3) * -3=-6k-9$

$2k+2-6k-9=1$

Simplify: $-4k-7=1$

Add 7 to both sides: $-4k=8$

Divide both sides by -4: $k=-2$.