Question

find the value of k if x =√2,y=3 is a solution of the equation √3x+√6y=k
a)2√6
b)3√6
c)5√6
d)4√6
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Answer 1

Answer:

Given Equation :

$\sqrt{3 } x + \sqrt{6} y = k$

x = √2 and y = 3 is a solution of the given equation.

Hence ,

$( \sqrt{3} \times \sqrt{2} ) + ( \sqrt{6} \times 3) = k \\ = > k = \sqrt{6 } + 3 \sqrt{6} \\ = > k = 4 \sqrt{6}$

Hence , the required value of k is 4√6

ANSWER : (d) 4√6

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Step-by-step explanation:

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