Question

Find the value of k, if X=2y=1 is a solution of the equation 2x+3y+k=0​

Answer 1

Answer:

Given equation, 2x+3y=k

x=2,y=1 is solution of resultant equation.

2(2)+3(1)=k

∴k=7

∴  Resultant equation is 2x+3y=7

At x=0,2(0)+3y=7

y=  

3

7

​  

 

At  y=0,2x+3(0)=7

x=  

2

7

​  

 

∴(0,  

3

7

​  

) and (  

2

7

​  

,0) are two more solutions of resultant equations.

Step-by-step explanation:

Answer 2

Answer:

-7/2

Step-by-step explanation:

here ,

X=1

y=1/2

then given equation is..

2x+ 3y+k=0

=2(1)+3(1/2)+k=0

=2+3/2+k=0

=7/2+k=0

=k=-7/2