Question

find the value of k, if (x+3)
a factor of 3x²+kx+6​

Answer 1

Answer:

k=11

Step-by-step explanation:

x+3=0

=×=-3

p(x)=3x2+kx+6

p(-3)=3×(-3)2+k×-3+6

=3×9-3k+6

=27-3k+6

=27+6-3k

=33-3k=0

=-3k=-33

=k=33/3

=k=11

Answer 2

Answer:

(x+3) = x + 3 = 0

x = 0 - 3

x = -3

Since (x+3) is the factor of 3x^2 +kx + 6

And (x+3) = -3

Therefore,

3 × (-3)^2 + k × (-3) + 6 = 0

3 × 9 + (-3k) + 6 = 0

27 + 6 -3k = 0

33 = 3k

k = 33/3

k = 11