Question

Find the value of k, if x=-3 and y=2 is a solution of kx-3y-12=0​

Answer 1

Answer:

K×-3-3×2-12=0

-3k-6-12=0

-3k-18=0

-3k=0+18

-3k=18

k=18/-3

K=-6

ANSWER=-6

Step-by-step explanation:

1st put x=-3 in Kx and y=2in 3y

then,Simply Solve the sum..

ANSWER=-6

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