find the value of k if (x-3) is a factor of 2x3-5x2+3x+k
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Answered by
13
Answer:
x-3=0
x=3
f(x)=2(3)^3-5(3)^2+3(3)+k=0
2(27)-5(9)+9+k=0
54-45+9+k=0
9+9+k=0
18+k=0
k= -18
Answered by
7
x-3=0 then x=3 value of k=-5
2×3-5×2+3×3+k =0
6-10+9+k =0
5+k =0
k =-5
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