Question

find the value of k if (x-3) is a factor of 2x3-5x2+3x+k​

Answer 1

Answer:

x-3=0

x=3

f(x)=2(3)^3-5(3)^2+3(3)+k=0

2(27)-5(9)+9+k=0

54-45+9+k=0

9+9+k=0

18+k=0

k= -18

Answer 2

x-3=0 then x=3 value of k=-5

2×3-5×2+3×3+k =0

6-10+9+k =0

5+k =0

k =-5