find the value of K, if (x+3) is a factor of 3xsq+kx+6
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Answer:
k=11
Step-by-step explanation:
X+3=0
X= -3
3x²+kx+6=0
3(-3)²+k(-3)+6=0
3(9)-3k+6=0
27-3k+6=0
33-3k=0
-3k= -33
k= -33/-3
k=11
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