Question

Find the value of k if x-3
is a factor of k²x² - kx² + 3 kx-k
​

Answer 1

explanation:

Let p(x) = k²x³ - kx² + 3kx - k

Given x - 3 is a factor of k²x³ - kx² + 3kx - k

Then x - 3 = 0

Since, x = 3 is a zero of the p(x), then p(3) = 0

Thus, substituting in the equation -

= k²(3)³ - k(3)² + 3k(3) - k = 0

= 27k² - 9k + 9k - k = 0

= 27k² - k = 0

=k(27k - 1) = 0

Case 1, k = 0

Case 2, 27k - 1 = 0

= k = 1/27

Therefore, the required value of k is either 1/27 or 0.

Answer 2

Step-by-step explanation:

Find the value of k if x-3 is a factor k²x² - kx² + 3 kx-k