find the value of k if x-3 is a factor of k²x³-kx²+x+6
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Step-by-step explanation:
f(x)=k²x³-kx²+x+6. ; factor. x-3
Find:-
k=?
solution:-
f(3)=k²(27)-k(9)+3+6=0
27k²-9k+9=0
3k²-k+1=0
k=[1+-√(-11)]/6
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