Question

Find the value of k if x-3 is a factor of kx^2-kx-2

Answer 1

Answer:

Heres your answer

By factor theorem ...

x-3=0

x=3

so

$p(x) = k {x}^{2} - kx - 2 \\ \\ p(3) = k {3}^{2} - 3k - 2 = 0 \\ \\ 9k - 3k - 2 = 0 \\ \\ 6k = 2 \\ \\ k = \frac{2}{6} = \frac{1}{3} \\ \\ \\ so \: k = \frac{1}{3}$

K =1/3

Hope it helps!