Question

Find the value of k, if x–3 is a factor of p(x)=x2–2x−k.​

Answer 1

Answer:

(x−3) is a factor of p(x).

p(x)=x2−k2x+k

p(3)=0

⟹(−3)2−k2(3)+k=0⟹3k2−k−9=0

solving this equation using quadratic formula 

k=61±12−4(3)(−9)

k=61±109

$\huge\mathfrak\red{∆Stalwart King}$

Answer 2

Solution:-

x-3=0

x=3

Putting value of x

p(x)=x2–2x−k.

x²-2x-k=0

(3)²-2(3)-k=0

9-6-k=0

-k=-3

k=3