Question

find the value of k, if x=-3 is a zero of the polynomial of (3x²+kx+6)​

Answer 1

Answer:

3(-3)²+k(-3)+6

27-3k+6

43-3k=0

k=43/3 OK friend this is urs

Answer 2

Answer:

If x+3 is a factor of the given equation then x = -3 must satisfy the equation.

Substituting the value x = -3 we get,

3(-3)^2 -3k + 6 = 0

3k = 33

k = 11