Question

Find the value of k, if (x+3) is factor of 3x^2+kx+6.

Answer 1

Question:-

Find the value of k, if (x + 3) is a factor of

${3x}^{2} + kx + 6$

Solution:-

Given,

(x + 3) is a factor of say p(x) = ${3x}^{2} + kx + 6$

Then,

$= > x + 3 = 0 = > x = - 3$

-3 is a root of p(x)

So,

$3 {( - 3)}^{2} + k( - 3) + 6 = 0$

$27 - 3k + 6 = 0$

$33 - 3k = 0$

$33 = 3k$

$k = \frac{33}{3} = 11$

So, value of k is 11