find the value of 'k ' if x=3 ,y=4 is a solution of the equation 2x+3y=k. find one more solution of the resultant equation
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Answered by
7
x = 3 , y = 4
2x+3y=k -(i)
Now evaluating the values in (i)
2(3) + 3(4) =k
=> 6 + 12 = k
=> k = 18
So equation is 2x + 3y = 18
Then we can find other zeroes by putting x=0 and y=0 respectively.
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Answered by
2
2x+3y=k
2(3)+3(4)=k
6+12=k
18=k
The other solution :
Let x=3
2(3)+3y=0
6+3y=0
3y= -6
y= -6/3
y= - 2
(3, - 2)
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