Question

find the value of k .if x= 4 is the solution of the quaratic equation 3x²+ kx-2=0​

Answer 1

Answer:

hello

Step-by-step explanation:

GIVEN

one root of the equation 3x2-kx-2=0 is 2

x = 2

Place the value of x in 3x2-kx-2=0

3(2)^2 - k(2) - 2 = 0

(3 x 4) - 2k - 2 = 0

12 - 2 - 2k = 0

10 - 2k = 0

10 = 2k

10 / 2 = k

5 = k

Now the equation is 3x^2 -5x - 2 = 0

Factorize :

3x^2 - 6x + x - 2 = 0

3x (x - 2) + 1 (x - 2) = 0

(3x + 1) (x - 2) = 0

3x + 1 = 0 & x - 2 = 0

3x = - 1 & x = 2

x = - 1 / 3 & x = 2

Therefore, the other root is - 1 / 3

Hope Helpful..................

                                     -Jai

Answer 2

Answer:

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