find the value of k if x+5 is a factor of the following 2x³+kx²-11x-30
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Answered by
0
Answer:
Step-by-step explanation:
since we know x+5 is the factor of p(x)=2x³+kx²-11x-30
lets find the zero of g(x)=x+5
g(x)=x+5=0
g(x)=x= -5
now, that we have the zero of g(x) lets put the value in p(x)
p(x)=2x³+kx²-11x-30
p(-5)=2(-5)³+k(-5)-11(-5)-30
=2(-125)-5k+55-30
=-240-5k+25
=265-5k
now lets solve the above answer to find k
265-5k=0
265=5k
265/5=k
53=k
k=53
hope it helps!! :)
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Answered by
2
Answer:
arey bhai sorry. mat bolo we can be make friends
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