Question

Find the value of k, if x + k is factor of the polynomials:

(i)x3–(k2–1)x + 3 (ii) – 4x3 + 4x2 + 4kx – k​

Answer 1

Step-by-step explanation:

Consider the given polynomial.

$x 4 −k 2 x 2 +3x−6k$

Since, x+k is the factor of given polynomial  

So, put x=−k

Therefore,

$(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4 −3k−6k=0−9k=0k=0$

Hence, the value of k is 0.