Question

find the value of k if x minus 1 is a factor of 2 X square + kx + root 2​

Answer 1

Answer:

$given \\( x - 1) \: is \: a \: factor \: of \: 2 {x}^{2} + kx + \sqrt{2} \\ k = \\ x = - 1 \\ 2 {x}^{2} + kx + \sqrt{2} = 0 \\ 2( { - 1}^{2}) + k( - 1) + \sqrt{2} = 0 \\ 2(1) - k + \sqrt{2} = 0 \\ 2 + \sqrt{2 } = k \\ k = 2 + \sqrt{2}$