find the value of k if x minus 1 is a factor of P of X in each of the following cases where as P of x is equal to 2 X square + 6 + root 2
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Hii friend,
(X-1) Is a factor of the given polynomial.
X = 1
P(X) = 2X²+6+✓2
P(1) = 2 × (1)² + ✓2
= (2+✓2)
K isn't given in polynomial. So P(1) = 2+✓2
HOPE IT WILL HELP YOU.... :-)
(X-1) Is a factor of the given polynomial.
X = 1
P(X) = 2X²+6+✓2
P(1) = 2 × (1)² + ✓2
= (2+✓2)
K isn't given in polynomial. So P(1) = 2+✓2
HOPE IT WILL HELP YOU.... :-)
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2
use calculator why need to ask us?
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