Question

find the value of k if x minus 1 is a factor of X in each of the following cases p (x) is equal to x square 2 + kx +
$\sqrt{2}$
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Answer 1

Answer:

sorry i hate maths

Step-by-step explanation:

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Answer 2

Answer:-(1+√2)

Step-by-step explanation:

p(x)=x^2+Kx+√2

Since (x-1) is a factor, we substitute it in the function

p(1)=1^2+K+√2

Also,p(1)=p(1-1)=0

Then,

1+K+√2=0

K+(1+√2)=0

K=-(1+√2)

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