Question

find the value of k if x minus 1 is a factor of x square + X + k

Answer 1

root will be 1..
1^2+1+k=0..
k=-2

Answer 2

${x}^{2} + x + k$
Given
$x - 1 \: \: is \: a \: factor \:$
THEREFORE
$x - 1 = 0$
$x = 1 \\ substituting \: the \: value\: of\: x \: in \\ \: the \: above \: equation \: we \: get$
$(1) ^{2} + 1 + k = 0$
$2 + k = 0$
$k = - 2 \: ans$
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