Question

find the value of k if x minus 2 is a factor of the polynomial P bracket X= kxsquare minus root 2 X + 1​

Answer 1

Answer:

given

$p{x} = kx {}^{2} - \sqrt{2x} + 1$

given gx is factors of given px

x-2=0

x=2

putting x=2

p(2)=k2²-√2×2+1=0

$4k - 2 \sqrt{2} + 1 = 0$

now we get

$k = \frac{2 \sqrt{2 } - 1}{4}$

Answer 2

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