find the value of k if x minus 3 is a factor of K square x cube minus kx square + 3kx minus k
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K square x cube - 27 K square -9 K square x square - 27 ke x minus kx square minus 9 K + 6 k x + 3 k x - 9 - k
K square x cube - 27 K square -9 K square x square - 27 ke x minus kx square minus 9 K + 6 k x + 3 k x - 9 - k
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Answered by
83
Answer:
g(x)=x-3
g(x)=0
0=x-3
3=x
put the value of x in k²x³-kx²+3kx-k
0=k²3³-k3²+3k3-k
let us collaborate k together and solve for 3 as x
0=27k²-9k+6k-k
0=27k²-3k
3k=27k²
k=27k²/3
k=9k²
9k²-k
8k
k=8
Step-by-step explanation:
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