Find the value of k, if x=z, y=1 is a solution of 2x+3y=k.
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Answered by
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Putting the values of x and y in the given equation,we get
2z+3*1=k
2z+3=k.
k=2z+3
2z+3*1=k
2z+3=k.
k=2z+3
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Answered by
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We are given that x=z and y=1
So, 2×z+3×1=k
By factor theorem;
2z+3-k=0 {as x=z and y=1 is a solution}
2z-k=0-3
K=-3-2z
Calculation will not give an exact answer as long as value of z is not specified.
So, 2×z+3×1=k
By factor theorem;
2z+3-k=0 {as x=z and y=1 is a solution}
2z-k=0-3
K=-3-2z
Calculation will not give an exact answer as long as value of z is not specified.
last step is wrong
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