Find the value of k if x2+(k+2) x+(3k-2)=0 has equal roots
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HEYA!
The answer is in the attachment provided. Please refer to it once.
Hope this helps mate!
The answer is in the attachment provided. Please refer to it once.
Hope this helps mate!
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Given equation :- x² + ( k + 2 ) x + ( 3k - 2 )
• If a equation has equal roots than it's discriminant is equal to Zero
i.e., Discriminant ( D ) = 0
and ,
D = b² - 4ac
0 = ( k + 2 )² - 4 × 1 × ( 3k - 2 )
0 = k² + 4 + 4k - 12k + 8
0 = k² - 8k + 12
0 = k² - 6k - 2k + 12
0 = k ( k - 6 ) - 2 ( k - 6 )
0 = ( k - 2 ) ( k - 6 )
• ( k - 2 ) = 0
k = 2
• ( k - 6 ) = 0
k = 6
Hence , for both the value of k that is 3 and 6 the equation will have the equal roots !!
• If a equation has equal roots than it's discriminant is equal to Zero
i.e., Discriminant ( D ) = 0
and ,
D = b² - 4ac
0 = ( k + 2 )² - 4 × 1 × ( 3k - 2 )
0 = k² + 4 + 4k - 12k + 8
0 = k² - 8k + 12
0 = k² - 6k - 2k + 12
0 = k ( k - 6 ) - 2 ( k - 6 )
0 = ( k - 2 ) ( k - 6 )
• ( k - 2 ) = 0
k = 2
• ( k - 6 ) = 0
k = 6
Hence , for both the value of k that is 3 and 6 the equation will have the equal roots !!
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